12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

- Code: Select all
`// Calculate (square of sum) - (sum of square) for first n natural numbers`

: pe006(n) // ( n -- n )

{

0 #+ n seqEach sq // Square of sum

0 #[ sq + ] n seqEach - // Sum of squares and substract

}